(5y-7)(2y^2-3y+1)=

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Solution for (5y-7)(2y^2-3y+1)= equation:


Simplifying
(5y + -7)(2y2 + -3y + 1) = 0

Reorder the terms:
(-7 + 5y)(2y2 + -3y + 1) = 0

Reorder the terms:
(-7 + 5y)(1 + -3y + 2y2) = 0

Multiply (-7 + 5y) * (1 + -3y + 2y2)
(-7(1 + -3y + 2y2) + 5y * (1 + -3y + 2y2)) = 0
((1 * -7 + -3y * -7 + 2y2 * -7) + 5y * (1 + -3y + 2y2)) = 0
((-7 + 21y + -14y2) + 5y * (1 + -3y + 2y2)) = 0
(-7 + 21y + -14y2 + (1 * 5y + -3y * 5y + 2y2 * 5y)) = 0
(-7 + 21y + -14y2 + (5y + -15y2 + 10y3)) = 0

Reorder the terms:
(-7 + 21y + 5y + -14y2 + -15y2 + 10y3) = 0

Combine like terms: 21y + 5y = 26y
(-7 + 26y + -14y2 + -15y2 + 10y3) = 0

Combine like terms: -14y2 + -15y2 = -29y2
(-7 + 26y + -29y2 + 10y3) = 0

Solving
-7 + 26y + -29y2 + 10y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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